X Trench Run Math Today
That matches the movie’s tension — only a few minutes from “begin your attack run” to firing. The proton torpedoes must turn 90° downward into the exhaust port. But with a magnetic “bend” (in-universe), the real math is a gravity-assisted turn , similar to a ballistic curve.
To hit a 2 m wide port from a horizontal offset of zero (directly above), the required vertical acceleration: x trench run math
[ \textLead angle \theta = \arctan\left( \fracv_\textlateralv_\texttorpedo \right) ] That matches the movie’s tension — only a
[ a = \frac2(20)(100^2)10^2 = \frac40 \cdot 10,000100 = 4,000 \ \textm/s^2 \ (\approx 408g) ] 000100 = 4