[ y = \frac{1}{C - 2x^3} ]
[ \int y^{-2} , dy = \int 6x^2 , dx ]
[ y = \frac{1}{-2x^3 - C} ]
Rewrite the equation so that all (y)-terms are on one side and all (x)-terms are on the other: solve the differential equation. dy dx = 6x2y2
[ y = \frac{1}{C - 2x^3} ]
[ \int y^{-2} , dy = \int 6x^2 , dx ]
[ y = \frac{1}{-2x^3 - C} ]
Rewrite the equation so that all (y)-terms are on one side and all (x)-terms are on the other:
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